Работаю на Денвере 3, phpMyAdmin 2.6.1, MySQL 5.0.45.
Пишет Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in Z:\home\localhost\www\php\mysql.php on line 16
Вот код:
<?php
$db = mysql_connect("localhost", "alex", "12345");
mysql_select_db("firstbd", $db);
$result = mysql_query("SELECT * FROM firma", $db);
$myrow = mysql_fetch_array($result);
echo $myrow ["name"];
?>
